What is expand (n-k-1)!(n-k) ?

The solution to expand (n-k-1)!(n-k) is n(n-k-1)!-k(n-k-1)!

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expand (n-k-1)!(n-k)

expand

(n - k - 1)! (n - k)

n (n - k - 1)! - k (n - k - 1)!

Solution steps

(n - k - 1)! (n - k)

Apply the distributive law:

a (b - c) = ab - a c

a = (n - k - 1)!, b = n, c = k

= (n - k - 1)! n - (n - k - 1)! k

= n (n - k - 1)! - k (n - k - 1)!

\frac{( - 2 t + 6 ) ( 2 t - 3 )}{t ^{2}}

(4, 2, 3) x (- 2, 0, - 1)

\frac{0.9 s}{( s - 0.1 ) ( x + 0.2 )}

(e^{a} + e^{b}) \cdot e^{a}

(- 0.8) (- 1.8) (- 2.6)

What is expand (n-k-1)!(n-k) ?
The solution to expand (n-k-1)!(n-k) is n(n-k-1)!-k(n-k-1)!