What is expand (x^2-3x-1)/(x(x^2+9)) ?

The solution to expand (x^2-3x-1)/(x(x^2+9)) is (x^2-3x-1)/(x^3+9x)

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expand (x^2-3x-1)/(x(x^2+9))

expand

\frac{x ^{2} - 3 x - 1}{x ( x ^{2} + 9 )}

\frac{x ^{2} - 3 x - 1}{x ^{3} + 9 x}

Solution steps

\frac{x ^{2} - 3 x - 1}{x ( x ^{2} + 9 )}

Expand

x (x^{2} + 9) : x^{3} + 9 x

= \frac{x ^{2} - 3 x - 1}{x ^{3} + 9 x}

\frac{( 2 x - 1 ) ( 2 x + 1 )}{9 x ^{4}}

(3 y - 1) d y

\frac{1 - s ( 1 - p )}{1 - s ( 1 - x )}

\frac{( 3 c + 4 ) ( 3 c - 2 )}{144}

(ln (x) + 1) \cdot (2 ln (x) - 1)

What is expand (x^2-3x-1)/(x(x^2+9)) ?
The solution to expand (x^2-3x-1)/(x(x^2+9)) is (x^2-3x-1)/(x^3+9x)