What is expand (f\circ g)x^2(4x-7) ?

The solution to expand (f\circ g)x^2(4x-7) is 4\circ fgx^3-7\circ fgx^2

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expand (f\circ g)x^2(4x-7)

expand

(f \circ g) x^{2} (4 x - 7)

4 \circ f g x^{3} - 7 \circ f g x^{2}

Solution steps

(f \circ g) x^{2} (4 x - 7)

= x^{2} (\circ f g) (4 x - 7)

Apply the distributive law:

a (b - c) = ab - a c

a = (f \circ g) x^{2}, b = 4 x, c = 7

= (f \circ g) x^{2} \cdot 4 x - (f \circ g) x^{2} \cdot 7

= 4 x^{2} x (\circ f g) - 7 x^{2} (\circ f g)

Simplify

4 x^{2} x (\circ f g) - 7 x^{2} (\circ f g) : 4 \circ f g x^{3} - 7 \circ f g x^{2}

= 4 \circ f g x^{3} - 7 \circ f g x^{2}

(f (x) = 5 x - 2^{3}) f (- 4)

\frac{d}{d t} ((t) (- k (t - t a)))

x (3 x - 2 y = 0)

- 8 x^{7} y^{4} (- 2 x y + 4 x, y^{5})

(3 - x) - 1

What is expand (f\circ g)x^2(4x-7) ?
The solution to expand (f\circ g)x^2(4x-7) is 4\circ fgx^3-7\circ fgx^2