What is we^{i(wt+pi/2)} ?

The solution to we^{i(wt+pi/2)} is wcos((pi+2wt)/2)+iwsin((pi+2wt)/2)

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simplify we^{i(wt+pi/2)}

simplify

w e^{i (wt + \frac{π}{2})}

w cos (\frac{π + 2 wt}{2}) + i w sin (\frac{π + 2 wt}{2})

Solution steps

w e^{i (wt + \frac{π}{2})}

e^{i (wt + \frac{π}{2})} = cos (\frac{2 wt + π}{2}) + i sin (\frac{2 wt + π}{2})

= w (cos (\frac{2 wt + π}{2}) + i sin (\frac{2 wt + π}{2}))

Rewrite

w (cos (\frac{2 wt + π}{2}) + sin (\frac{2 wt + π}{2}) i)

in standard complex form:

w cos (\frac{2 wt + π}{2}) + w sin (\frac{2 wt + π}{2}) i

= w cos (\frac{2 wt + π}{2}) + w sin (\frac{2 wt + π}{2}) i

\frac{21}{( x + 8 ) ( x - 4 )}

\frac{( x - 6 ) ^{2}}{36}

(3 y - 2 x) d x - (2 y - x) d y

- \frac{L ^{2} ( 3 P + 2 W L )}{48}

(- 8, - 3) y (- 1, - 2)

What is we^{i(wt+pi/2)} ?
The solution to we^{i(wt+pi/2)} is wcos((pi+2wt)/2)+iwsin((pi+2wt)/2)