What are the solutions to the equation 2x=7-x^2 ?

The solutions to the equation 2x=7-x^2 are x=-1-2sqrt(2),x=2sqrt(2)-1

Find the zeros of 2x=7-x^2

The zeros of 2x=7-x^2 are x=-1-2sqrt(2),x=2sqrt(2)-1

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2 x = 7 - x^{2}

x = - 1 - 22, x = 22 - 1

Decimal Notation

x = - 3.82842 \dots, x = 1.82842 \dots

Solution steps

2 x = 7 - x^{2}

Switch sides

7 - x^{2} = 2 x

Move

2 x

to the left side

7 - x^{2} - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} - 2 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) \cdot 7}{2 ( - 1 )}

(- 2)^{2} - 4 (- 1) \cdot 7 = 42

x_{1, 2} = \frac{- ( - 2 ) \pm 4 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 2}{2 ( - 1 )}, x_{2} = \frac{- ( - 2 ) - 4 2}{2 ( - 1 )}

x = \frac{- ( - 2 ) + 4 2}{2 ( - 1 )} : - 1 - 22

x = \frac{- ( - 2 ) - 4 2}{2 ( - 1 )} : 22 - 1

The solutions to the quadratic equation are:

x = - 1 - 22, x = 22 - 1

x^{3} - 2 x^{2} - 5 x + 6

- 5 u = - 6

\frac{4}{3} (x - 3) \leq \frac{2}{3}

y + 10 \geq 13 or \frac{5 y + 1}{2} < 3

3 x (x + 1) + 7 (x + 1)

What are the solutions to the equation 2x=7-x^2 ?
The solutions to the equation 2x=7-x^2 are x=-1-2sqrt(2),x=2sqrt(2)-1
Find the zeros of 2x=7-x^2
The zeros of 2x=7-x^2 are x=-1-2sqrt(2),x=2sqrt(2)-1