What is expand (-7x^2+4x-5)-(Q(x)=2x-7) ?

The solution to expand (-7x^2+4x-5)-(Q(x)=2x-7) is -7x^2+4x-5-Q(x)=2x+7

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expand (-7x^2+4x-5)-(Q(x)=2x-7)

expand

(- 7 x^{2} + 4 x - 5) - (Q (x) = 2 x - 7)

- 7 x^{2} + 4 x - 5 - Q (x) = 2 x + 7

Solution steps

(- 7 x^{2} + 4 x - 5) - (Q (x) = 2 x - 7)

= (- 7 x^{2} + 4 x - 5) - (2 = x Q (x) - 7)

- (Q (x) = 2 x - 7) : - Q (x) = 2 x + 7

(- 7 x^{2} + 4 x - 5) - Q (x) = 2 x + 7

Expand

(- 7 x^{2} + 4 x - 5) - Q (x) : - 7 x^{2} + 4 x - 5 - Q (x)

- 7 x^{2} + 4 x - 5 - Q (x) = 2 x + 7

\frac{3}{( 2 x - 1 ) ^{8}}

3 (y^{2} + 2 x y \frac{d y}{d x})

\frac{5 ( x - 1 )}{2 x + 3}

\frac{( x - 5 )}{( 2 x ( 3 x - 4 ) )}

(\frac{1 + r}{r})^{2}

What is expand (-7x^2+4x-5)-(Q(x)=2x-7) ?
The solution to expand (-7x^2+4x-5)-(Q(x)=2x-7) is -7x^2+4x-5-Q(x)=2x+7