What is expand ((n-1)/n y)-y ?

The solution to expand ((n-1)/n y)-y is -y/n

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expand ((n-1)/n y)-y

expand

(\frac{n - 1}{n} y) - y

- \frac{y}{n}

Solution steps

(\frac{n - 1}{n} y) - y

Remove parentheses:

(a) = a

= \frac{n - 1}{n} y - y

\frac{n - 1}{n} y = \frac{n y - y}{n}

= \frac{n y - y}{n} - y

Convert element to fraction:

y = \frac{y n}{n}

= \frac{n y - y}{n} - \frac{y n}{n}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{n y - y - y n}{n}

n y - y - y n = - y

= \frac{- y}{n}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{y}{n}

- 5 (p^{2})

\frac{s}{( s ^{2} + 1 ) ( s ^{2} + 4 )}

K \cdot y \cdot (e^{t^{2}} - e)

x - 4^{2}

\frac{x ^{2}}{s \cdot ( s + x ) ^{2}}