What is expand (sin((n-2)pi))/((n-2)pi) ?

The solution to expand (sin((n-2)pi))/((n-2)pi) is 0

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expand (sin((n-2)pi))/((n-2)pi)

expand

\frac{sin ( ( n - 2 ) π )}{( n - 2 ) π}

0

Solution steps

\frac{sin ( ( n - 2 ) π )}{( n - 2 ) π}

Expand

(n - 2) π : πn - 2 π

= \frac{sin ( π ( n - 2 ) )}{πn - 2 π}

Expand

(n - 2) π : πn - 2 π

= \frac{sin ( πn - 2 π )}{πn - 2 π}

Rewrite using trig identities

= \frac{sin ( πn )}{πn - 2 π}

Use the basic trigonometric identity:

sin (nπ) = 0

= \frac{0}{- 2 π + nπ}

Apply rule

\frac{0}{a} = 0, a \neq = 0

= 0

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\frac{( x + 3 ) 7}{5}

\frac{x ( - 12 x + 13 )}{7 ( 10 x - 1 )}

What is expand (sin((n-2)pi))/((n-2)pi) ?
The solution to expand (sin((n-2)pi))/((n-2)pi) is 0