What is expand ((2x^2-3)^2)/4 ?

The solution to expand ((2x^2-3)^2)/4 is x^4-3x^2+9/4

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expand ((2x^2-3)^2)/4

expand

\frac{( 2 x ^{2} - 3 ) ^{2}}{4}

x^{4} - 3 x^{2} + \frac{9}{4}

Solution steps

\frac{( 2 x ^{2} - 3 ) ^{2}}{4}

(2 x^{2} - 3)^{2} = 4 x^{4} - 12 x^{2} + 9

= \frac{4 x ^{4} - 12 x ^{2} + 9}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x ^{4} - 12 x ^{2} + 9}{4} = \frac{4 x ^{4}}{4} - \frac{12 x ^{2}}{4} + \frac{9}{4}

= \frac{4 x ^{4}}{4} - \frac{12 x ^{2}}{4} + \frac{9}{4}

Divide the numbers:

\frac{4}{4} = 1

= x^{4} - \frac{12 x ^{2}}{4} + \frac{9}{4}

Divide the numbers:

\frac{12}{4} = 3

= x^{4} - 3 x^{2} + \frac{9}{4}

sec^{2} (\frac{2 π}{3})

10 (- \frac{1}{e ^{3}} - 2)

(1 - u^{2}) u^{2} - d u

y^{'} (x) (2 x + 7)^{3}

(x + 4) (x + 4)^{'}

What is expand ((2x^2-3)^2)/4 ?
The solution to expand ((2x^2-3)^2)/4 is x^4-3x^2+9/4