What is expand (x+5)e^{0.02x+1} ?

The solution to expand (x+5)e^{0.02x+1} is e^{0.02x+1}x+5e^{0.02x+1}

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expand (x+5)e^{0.02x+1}

expand

(x + 5) e^{0.02 x + 1}

e^{0.02 x + 1} x + 5 e^{0.02 x + 1}

Solution steps

(x + 5) e^{0.02 x + 1}

= e^{0.02 x + 1} (x + 5)

Apply the distributive law:

a (b + c) = ab + a c

a = e^{0.02 x + 1}, b = x, c = 5

= e^{0.02 x + 1} x + e^{0.02 x + 1} \cdot 5

= e^{0.02 x + 1} x + 5 e^{0.02 x + 1}

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What is expand (x+5)e^{0.02x+1} ?
The solution to expand (x+5)e^{0.02x+1} is e^{0.02x+1}x+5e^{0.02x+1}