What is expand (e^{-2x}(e^{4x}+1))/2 ?

The solution to expand (e^{-2x}(e^{4x}+1))/2 is (e^{2x})/2+(e^{-2x})/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (e^{-2x}(e^{4x}+1))/2

expand

\frac{e ^{- 2 x} ( e ^{4 x} + 1 )}{2}

\frac{e ^{2 x}}{2} + \frac{e ^{- 2 x}}{2}

Solution steps

\frac{e ^{- 2 x} ( e ^{4 x} + 1 )}{2}

Expand

e^{- 2 x} (e^{4 x} + 1) : e^{2 x} + e^{- 2 x}

= \frac{e ^{2 x} + e ^{- 2 x}}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{e ^{2 x} + e ^{- 2 x}}{2} = \frac{e ^{2 x}}{2} + \frac{e ^{- 2 x}}{2}

= \frac{e ^{2 x}}{2} + \frac{e ^{- 2 x}}{2}

ro t a c i o na l (x^{3} y + y^{5} z^{2})

so l v e (x - 6) (x - 5)

e^{x (x + 2) y}

7 x^{(\frac{1}{2})}

(3 d + 1) (e - 2)

What is expand (e^{-2x}(e^{4x}+1))/2 ?
The solution to expand (e^{-2x}(e^{4x}+1))/2 is (e^{2x})/2+(e^{-2x})/2