What is expand ((x+1)^3)/(x^4) ?

The solution to expand ((x+1)^3)/(x^4) is 1/x+3/(x^2)+3/(x^3)+1/(x^4)

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expand ((x+1)^3)/(x^4)

expand

\frac{( x + 1 ) ^{3}}{x ^{4}}

\frac{1}{x} + \frac{3}{x ^{2}} + \frac{3}{x ^{3}} + \frac{1}{x ^{4}}

Solution steps

\frac{( x + 1 ) ^{3}}{x ^{4}}

(x + 1)^{3} = x^{3} + 3 x^{2} + 3 x + 1

= \frac{x ^{3} + 3 x ^{2} + 3 x + 1}{x ^{4}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} + 3 x ^{2} + 3 x + 1}{x ^{4}} = \frac{x ^{3}}{x ^{4}} + \frac{3 x ^{2}}{x ^{4}} + \frac{3 x}{x ^{4}} + \frac{1}{x ^{4}}

= \frac{x ^{3}}{x ^{4}} + \frac{3 x ^{2}}{x ^{4}} + \frac{3 x}{x ^{4}} + \frac{1}{x ^{4}}

Cancel

\frac{x ^{3}}{x ^{4}} : \frac{1}{x}

= \frac{1}{x} + \frac{3 x ^{2}}{x ^{4}} + \frac{3 x}{x ^{4}} + \frac{1}{x ^{4}}

Cancel

\frac{3 x ^{2}}{x ^{4}} : \frac{3}{x ^{2}}

= \frac{1}{x} + \frac{3}{x ^{2}} + \frac{3 x}{x ^{4}} + \frac{1}{x ^{4}}

Cancel

\frac{3 x}{x ^{4}} : \frac{3}{x ^{3}}

= \frac{1}{x} + \frac{3}{x ^{2}} + \frac{3}{x ^{3}} + \frac{1}{x ^{4}}

, a - p (x^{2} + 2 q x + q^{2})

\frac{2 \cdot 5 + 4}{5 - 5}

((3 - 6 sin (θ))^{2}) d θ

(2 a - 3 e) (4 a^{2} + 6 a e + 9 e)

(e^{2 x} + e^{x})^{3}

What is expand ((x+1)^3)/(x^4) ?
The solution to expand ((x+1)^3)/(x^4) is 1/x+3/(x^2)+3/(x^3)+1/(x^4)