What is expand (x^2-9x-12)/((x+2)(x-3)) ?

The solution to expand (x^2-9x-12)/((x+2)(x-3)) is (x^2-9x-12)/(x^2-x-6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x^2-9x-12)/((x+2)(x-3))

expand

\frac{x ^{2} - 9 x - 12}{( x + 2 ) ( x - 3 )}

\frac{x ^{2} - 9 x - 12}{x ^{2} - x - 6}

Solution steps

\frac{x ^{2} - 9 x - 12}{( x + 2 ) ( x - 3 )}

Expand

(x + 2) (x - 3) : x^{2} - x - 6

= \frac{x ^{2} - 9 x - 12}{x ^{2} - x - 6}

2 (v + 30 = 10)

(0, 0, - 2) (- 3, - 2, x)

\frac{1 + ( - 1 ) ^{x}}{2}

(- 7^{8}) 2

\frac{( 9 - ln ( x ) ) ^{2}}{36}

What is expand (x^2-9x-12)/((x+2)(x-3)) ?
The solution to expand (x^2-9x-12)/((x+2)(x-3)) is (x^2-9x-12)/(x^2-x-6)