What is expand (2x-y+3z=10)*(-3) ?

The solution to expand (2x-y+3z=10)*(-3) is -6x+3y-9z=10

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expand (2x-y+3z=10)*(-3)

expand

(2 x - y + 3 z = 10) \cdot (- 3)

- 6 x + 3 y - 9 z = 10

Solution steps

(2 x - y + 3 z = 10) (- 3)

= (- 3) (2 x - y + 3 \cdot 10 = z)

Distribute parentheses

(- 3) \cdot 2 x + (- 3) (- y) + (- 3) \cdot 3 z = 10

Apply minus-plus rules

+ (- a) = - a

(- 3) \cdot 2 x - (- 3) y + (- 3) \cdot 3 z = 10

Expand

(- 3) \cdot 2 x - (- 3) y + (- 3) \cdot 3 z : - 6 x + 3 y - 9 z

- 6 x + 3 y - 9 z = 10

1 - (\frac{4}{( x + 1 ) ^{2}})

\frac{1}{( a - b ) ( a + b )}

(y^{4}) x^{3} (3 e^{x} + C)

- 2 (j - 6 = - 18)

22.99 + 0.07 (22.99)

What is expand (2x-y+3z=10)*(-3) ?
The solution to expand (2x-y+3z=10)*(-3) is -6x+3y-9z=10