What is expand ((x-2)(x+8))/((x+1)(x-1)) ?

The solution to expand ((x-2)(x+8))/((x+1)(x-1)) is (x^2+6x-16)/(x^2-1)

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expand ((x-2)(x+8))/((x+1)(x-1))

expand

\frac{( x - 2 ) ( x + 8 )}{( x + 1 ) ( x - 1 )}

\frac{x ^{2} + 6 x - 16}{x ^{2} - 1}

Solution steps

\frac{( x - 2 ) ( x + 8 )}{( x + 1 ) ( x - 1 )}

Expand

(x + 1) (x - 1) : x^{2} - 1

= \frac{( x - 2 ) ( x + 8 )}{x ^{2} - 1}

Expand

(x - 2) (x + 8) : x^{2} + 6 x - 16

= \frac{x ^{2} + 6 x - 16}{x ^{2} - 1}

A (- 5, - 6) B (- 2, - 2)

(3 x + 7 y = - 12) (5)

\frac{x ^{2} - 3 x + 6}{x ( x - 2 )}

(2 - x) (x + 2 - x^{2}) d x

\frac{1}{s ^{2} ( s + 1 ) ( s + 2 )}

What is expand ((x-2)(x+8))/((x+1)(x-1)) ?
The solution to expand ((x-2)(x+8))/((x+1)(x-1)) is (x^2+6x-16)/(x^2-1)