What is expand (x+Δx)^2-4(x+Δx)+5 ?

The solution to expand (x+Δx)^2-4(x+Δx)+5 is x^2+2Δx^2+Δ^2x^2-4x-4Δx+5

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expand (x+Δx)^2-4(x+Δx)+5

expand

(x + Δ x)^{2} - 4 (x + Δ x) + 5

x^{2} + 2Δ x^{2} + Δ^{2} x^{2} - 4 x - 4Δ x + 5

Solution steps

(x + Δ x)^{2} - 4 (x + Δ x) + 5

Expand

- 4 (x + Δ x) : - 4 x - 4Δ x

= (x + Δ x)^{2} - 4 x - 4Δ x + 5

(x + Δ x)^{2} : x^{2} + 2Δ x^{2} + Δ^{2} x^{2}

= x^{2} + 2Δ x^{2} + Δ^{2} x^{2} - 4 x - 4Δ x + 5

(- 3, - 5, - 1) x (- 4, 5, 7)

\frac{1}{( x - 1 ) ( x + 2 ) ( 2 x + 1 )}

2 - 6 (5 + 2 [3 + 5 (8 - 7 \cdot, 8)])

\frac{( - 4 - i ) ^{7}}{( 2 - 3 i ) ^{5}}

\frac{1}{( 1 - n ) ^{2}}

What is expand (x+Δx)^2-4(x+Δx)+5 ?
The solution to expand (x+Δx)^2-4(x+Δx)+5 is x^2+2Δx^2+Δ^2x^2-4x-4Δx+5