What is expand-(9(y^2+9x^2))/(y^3) ?

The solution to expand-(9(y^2+9x^2))/(y^3) is -9/y-(81x^2)/(y^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-(9(y^2+9x^2))/(y^3)

expand

- \frac{9 ( y ^{2} + 9 x ^{2} )}{y ^{3}}

- \frac{9}{y} - \frac{81 x ^{2}}{y ^{3}}

Solution steps

- \frac{9 ( y ^{2} + 9 x ^{2} )}{y ^{3}}

Expand

9 (y^{2} + 9 x^{2}) : 9 y^{2} + 81 x^{2}

= - \frac{9 y ^{2} + 81 x ^{2}}{y ^{3}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 y ^{2} + 81 x ^{2}}{y ^{3}} = - (\frac{9 y ^{2}}{y ^{3}}) - (\frac{81 x ^{2}}{y ^{3}})

= - (\frac{9 y ^{2}}{y ^{3}}) - (\frac{81 x ^{2}}{y ^{3}})

Remove parentheses:

(a) = a

= - \frac{9 y ^{2}}{y ^{3}} - \frac{81 x ^{2}}{y ^{3}}

Cancel

\frac{9 y ^{2}}{y ^{3}} : \frac{9}{y}

= - \frac{9}{y} - \frac{81 x ^{2}}{y ^{3}}

x (1 - lo g_{10} (5))

(2 x - 1) e^{2}

(4 ln (x) + c) (x^{2})

x (u - 2) (u d x + x d u)

\frac{3 x + 1}{2 ( - 1 + 4 x )}

What is expand-(9(y^2+9x^2))/(y^3) ?
The solution to expand-(9(y^2+9x^2))/(y^3) is -9/y-(81x^2)/(y^3)