What is expand (2x(x-3))/(x-1) ?

The solution to expand (2x(x-3))/(x-1) is (2x^2-6x)/(x-1)

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expand (2x(x-3))/(x-1)

expand

\frac{2 x ( x - 3 )}{x - 1}

\frac{2 x ^{2} - 6 x}{x - 1}

Solution steps

\frac{2 x ( x - 3 )}{x - 1}

Expand

2 x (x - 3) : 2 x^{2} - 6 x

= \frac{2 x ^{2} - 6 x}{x - 1}

\frac{( ( 15 c + 2 ) ( 15 c - 2 ) )}{9}

1 1^{2}

\frac{( m + 12 ) ^{2}}{( n + 2 ) ^{4}}

- 2 x - (- 7 x - 10 = - (- 10 x - 1) - 1)

\frac{d}{d y} ((x) (2 x + 4 y))

What is expand (2x(x-3))/(x-1) ?
The solution to expand (2x(x-3))/(x-1) is (2x^2-6x)/(x-1)