What is expand-(3(s+3))/(s(s+2)(s-1)) ?

The solution to expand-(3(s+3))/(s(s+2)(s-1)) is -(3s+9)/(s^3+s^2-2s)

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expand-(3(s+3))/(s(s+2)(s-1))

expand

- \frac{3 ( s + 3 )}{s ( s + 2 ) ( s - 1 )}

- \frac{3 s + 9}{s ^{3} + s ^{2} - 2 s}

Solution steps

- \frac{3 ( s + 3 )}{s ( s + 2 ) ( s - 1 )}

Expand

s (s + 2) (s - 1) : s^{3} + s^{2} - 2 s

= - \frac{3 ( s + 3 )}{s ^{3} + s ^{2} - 2 s}

Expand

3 (s + 3) : 3 s + 9

= - \frac{3 s + 9}{s ^{3} + s ^{2} - 2 s}

\frac{5}{( 3 x - 2 ) ^{2}}

\frac{( x - 4 ) ( x + 1 )}{x - 3}

\frac{x ^{2} ( x + 1 )}{x + 2}

\frac{( 1 )}{( ( s ) ( s ^{2} + s + 1 ) )}

X (X^{2 + 7 Y - 3})

What is expand-(3(s+3))/(s(s+2)(s-1)) ?
The solution to expand-(3(s+3))/(s(s+2)(s-1)) is -(3s+9)/(s^3+s^2-2s)