What is the d/(dy)((m)(x^3+xy^2)) ?

The d/(dy)((m)(x^3+xy^2)) is 2mxy

What is the first d/(dy)((m)(x^3+xy^2)) ?

The first d/(dy)((m)(x^3+xy^2)) is 2mxy

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\frac{d}{d y} ((m) (x^{3} + x y^{2}))

2 m x y

Solution steps

\frac{d}{d y} ((m) (x^{3} + x y^{2}))

Treat

m, x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= m \frac{d}{d y} (x^{3} + x y^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= m (\frac{d}{d y} (x^{3}) + \frac{d}{d y} (x y^{2}))

\frac{d}{d y} (x^{3}) = 0

\frac{d}{d y} (x y^{2}) = 2 x y

= m (0 + 2 x y)

Simplify

= 2 m x y

(f \circ g) (x^{2} + 2 x - 7) (2 x - 9)

\frac{( x + 1 ) ( x - 2 )}{x}

(1 + e^{2 x}) (1 - e^{2 x})

e^{3 t} (y^{'} (t) + 3 y)

14 (6 x - 5 y = 1)

What is the d/(dy)((m)(x^3+xy^2)) ?
The d/(dy)((m)(x^3+xy^2)) is 2mxy
What is the first d/(dy)((m)(x^3+xy^2)) ?
The first d/(dy)((m)(x^3+xy^2)) is 2mxy