What is expand '2(x^2+3x-4)(4x+3) ?

The solution to expand '2(x^2+3x-4)(4x+3) is 8'x^3+30'x^2-14'x-24'

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expand '2(x^2+3x-4)(4x+3)

expand

^{'} 2 (x^{2} + 3 x - 4) (4 x + 3)

8' x^{3} + 30' x^{2} - 14' x - 24'

Solution steps

^{'} 2 (x^{2} + 3 x - 4) (4 x + 3)

= 2^{^{'}} (x^{2} + 3 x - 4) (4 x + 3)

Expand

(x^{2} + 3 x - 4) (4 x + 3) : 4 x^{3} + 15 x^{2} - 7 x - 12

=^{'} 2 (4 x^{3} + 15 x^{2} - 7 x - 12)

Expand

^{'} 2 (4 x^{3} + 15 x^{2} - 7 x - 12) : 8^{'} x^{3} + 3 0^{'} x^{2} - 1 4^{'} x - 2 4^{'}

= 8^{'} x^{3} + 3 0^{'} x^{2} - 1 4^{'} x - 2 4^{'}

5^{7}

\frac{5 x + 1}{( x + 1 ) ^{2}}

20 (1 - e^{- \frac{x}{30}})

x - 2^{4}

\frac{1}{2 ( 1 + x ^{2} )}

What is expand '2(x^2+3x-4)(4x+3) ?
The solution to expand '2(x^2+3x-4)(4x+3) is 8'x^3+30'x^2-14'x-24'