What is expand (k(2n+1-2k))/(n^2) ?

The solution to expand (k(2n+1-2k))/(n^2) is (2k)/n+k/(n^2)-(2k^2)/(n^2)

Popular >

expand (k(2n+1-2k))/(n^2)

expand

\frac{k ( 2 n + 1 - 2 k )}{n ^{2}}

\frac{2 k}{n} + \frac{k}{n ^{2}} - \frac{2 k ^{2}}{n ^{2}}

Solution steps

\frac{k ( 2 n + 1 - 2 k )}{n ^{2}}

Expand

k (2 n + 1 - 2 k) : 2 kn + k - 2 k^{2}

= \frac{2 kn + k - 2 k ^{2}}{n ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 kn + k - 2 k ^{2}}{n ^{2}} = \frac{2 kn}{n ^{2}} + \frac{k}{n ^{2}} - \frac{2 k ^{2}}{n ^{2}}

= \frac{2 kn}{n ^{2}} + \frac{k}{n ^{2}} - \frac{2 k ^{2}}{n ^{2}}

Cancel

\frac{2 kn}{n ^{2}} : \frac{2 k}{n}

= \frac{2 k}{n} + \frac{k}{n ^{2}} - \frac{2 k ^{2}}{n ^{2}}

(2 x + e^{x}) (x^{3} + 2 e^{x})

\frac{( 4 x + 9 )}{( x + 3 ) ( x - 3 )}

(2, - 6, 4) x (- 1, 3, 5)

\frac{h ( x + 2 ) - 2 x}{h ( x + 2 )}

det (λ - 1) (λ^{2} - 2 λ - 2)

What is expand (k(2n+1-2k))/(n^2) ?
The solution to expand (k(2n+1-2k))/(n^2) is (2k)/n+k/(n^2)-(2k^2)/(n^2)