What is expand (x^3-2x^2-5x)(x-1)' ?

The solution to expand (x^3-2x^2-5x)(x-1)' is x^3(x-1)'-2x^2(x-1)'-5x(x-1)'

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expand (x^3-2x^2-5x)(x-1)'

expand

(x^{3} - 2 x^{2} - 5 x) (x - 1)^{'}

x^{3} (x - 1)' - 2 x^{2} (x - 1)' - 5 x (x - 1)'

Solution steps

(x^{3} - 2 x^{2} - 5 x) (x - 1)^{'}

Distribute parentheses

= (x - 1)^{^{'}} x^{3} + (x - 1)^{^{'}} (- 2 x^{2}) + (x - 1)^{^{'}} (- 5 x)

Apply minus-plus rules

+ (- a) = - a

= x^{3} (x - 1)^{^{'}} - 2 x^{2} (x - 1)^{^{'}} - 5 x (x - 1)^{^{'}}

(1, - 2, 0) X (2, 1, 0)

[- (x - 6)]^{2}

\frac{k}{s ( s ^{2} + 9 s + 9 )}

(x^{3} - 6) \circ (3 x + 2)

(- 2, - 3) y (3, 2)

What is expand (x^3-2x^2-5x)(x-1)' ?
The solution to expand (x^3-2x^2-5x)(x-1)' is x^3(x-1)'-2x^2(x-1)'-5x(x-1)'