What is expand (2+j)e^{j^9t}+(2-j)e^{-9t} ?

The solution to expand (2+j)e^{j^9t}+(2-j)e^{-9t} is 2e^{j^9t}+je^{j^9t}+2e^{-9t}-je^{-9t}

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expand (2+j)e^{j^9t}+(2-j)e^{-9t}

expand

(2 + j) e^{j^{9} t} + (2 - j) e^{- 9 t}

2 e^{j^{9} t} + j e^{j^{9} t} + 2 e^{- 9 t} - j e^{- 9 t}

Solution steps

(2 + j) e^{j^{9} t} + (2 - j) e^{- 9 t}

= e^{j^{9} t} (2 + j) + e^{- 9 t} (2 - j)

Expand

e^{j^{9} t} (2 + j) : 2 e^{j^{9} t} + j e^{j^{9} t}

= 2 e^{j^{9} t} + j e^{j^{9} t} + (2 - j) e^{- 9 t}

Expand

e^{- 9 t} (2 - j) : 2 e^{- 9 t} - j e^{- 9 t}

= 2 e^{j^{9} t} + j e^{j^{9} t} + 2 e^{- 9 t} - j e^{- 9 t}

, (x^{2} + y^{2} = 25)

\frac{1}{( s + 2 ) ( s + 10 )}

\frac{z}{( z + 1 ) ( z + 2 )}

sin (π (1 - x))

(e^{- 2 x} + 1)^{2}

What is expand (2+j)e^{j^9t}+(2-j)e^{-9t} ?
The solution to expand (2+j)e^{j^9t}+(2-j)e^{-9t} is 2e^{j^9t}+je^{j^9t}+2e^{-9t}-je^{-9t}