What is expand 9cos(xy)(y+x(dy)/(dx)) ?

The solution to expand 9cos(xy)(y+x(dy)/(dx)) is 9cos(xy)y+9xcos(xy)(dy)/(dx)

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expand 9cos(xy)(y+x(dy)/(dx))

expand

9 cos (x y) (y + x \frac{d y}{d x})

9 cos (x y) y + 9 x cos (x y) \frac{d y}{d x}

Solution steps

9 cos (x y) (y + x \frac{d y}{d x})

Apply the distributive law:

a (b + c) = ab + a c

a = 9 cos (x y), b = y, c = x \frac{d y}{d x}

= 9 cos (x y) y + 9 cos (x y) x \frac{d y}{d x}

= 9 cos (x y) y + 9 x cos (x y) \frac{d y}{d x}

(5 x^{2} + x + 5) e^{x}

\frac{15 ( x + 3 y ) - 2}{30 ( x + 3 y ) - 20}

21 + 18

\frac{2 y - 3 x}{3} (7, - 9, - 5)

\frac{4}{( s ^{2} + 16 s ) ( s )}

What is expand 9cos(xy)(y+x(dy)/(dx)) ?
The solution to expand 9cos(xy)(y+x(dy)/(dx)) is 9cos(xy)y+9xcos(xy)(dy)/(dx)