What is expand ((3x-1)(3x+2))/(x^2) ?

The solution to expand ((3x-1)(3x+2))/(x^2) is 9+3/x-2/(x^2)

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expand ((3x-1)(3x+2))/(x^2)

expand

\frac{( 3 x - 1 ) ( 3 x + 2 )}{x ^{2}}

9 + \frac{3}{x} - \frac{2}{x ^{2}}

Solution steps

\frac{( 3 x - 1 ) ( 3 x + 2 )}{x ^{2}}

Expand

(3 x - 1) (3 x + 2) : 9 x^{2} + 3 x - 2

= \frac{9 x ^{2} + 3 x - 2}{x ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 x ^{2} + 3 x - 2}{x ^{2}} = \frac{9 x ^{2}}{x ^{2}} + \frac{3 x}{x ^{2}} - \frac{2}{x ^{2}}

= \frac{9 x ^{2}}{x ^{2}} + \frac{3 x}{x ^{2}} - \frac{2}{x ^{2}}

Cancel

\frac{9 x ^{2}}{x ^{2}} : 9

= 9 + \frac{3 x}{x ^{2}} - \frac{2}{x ^{2}}

Cancel

\frac{3 x}{x ^{2}} : \frac{3}{x}

= 9 + \frac{3}{x} - \frac{2}{x ^{2}}

(x, y) (x + 2 y - 2)

(- 1 + 2 j) (2, - 3)

6^{1}

\frac{3}{2 ( 3 x + 2 )}

e^{(x - 1)^{2}}

What is expand ((3x-1)(3x+2))/(x^2) ?
The solution to expand ((3x-1)(3x+2))/(x^2) is 9+3/x-2/(x^2)