What is expand f(t,x)(t=2+4e^{-2x}) ?

The solution to expand f(t,x)(t=2+4e^{-2x}) is tf(,tx)=2+4e^{-2x}f(,tx)

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expand f(t,x)(t=2+4e^{-2x})

expand

f (t, x) (t = 2 + 4 e^{- 2 x})

t f (, t x) = 2 + 4 e^{- 2 x} f (, t x)

Solution steps

f (t, x) (t = 2 + 4 e^{- 2 x})

= f (, t x) (2 = t + 4 e^{- 2 x})

Apply the distributive law:

a (b + c) = ab + a c

a = f (t, x), b = t = 2, c = 4 e^{- 2 x}

f (t, x) t = 2 + f (t, x) \cdot 4 e^{- 2 x}

t f (, t x) = 2 + 4 e^{- 2 x} f (, t x)

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1 - \frac{a ^{1}}{a ^{2}}

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What is expand f(t,x)(t=2+4e^{-2x}) ?
The solution to expand f(t,x)(t=2+4e^{-2x}) is tf(,tx)=2+4e^{-2x}f(,tx)