What is expand y(y^2-3y-x=0) ?

The solution to expand y(y^2-3y-x=0) is y^3-3y^2-xy=0

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expand y(y^2-3y-x=0)

expand

y (y^{2} - 3 y - x = 0)

y^{3} - 3 y^{2} - x y = 0

Solution steps

y (y^{2} - 3 y - x = 0)

= y (y^{2} - 3 y - 0 = x)

Distribute parentheses

= y y^{2} + y (- 3 y) + y (- x = 0)

Apply minus-plus rules

+ (- a) = - a

y y^{2} - 3 yy - x y = 0

Expand

y y^{2} - 3 yy - x y : y^{3} - 3 y^{2} - x y

y^{3} - 3 y^{2} - x y = 0

(- 2 x^{2} + 5 x) e^{4 x}

(x + x y) d y

\frac{1}{t ( l - t )}

\frac{3 ( 5 + 85 )}{5}

(2 x - 1) - (6 x)

What is expand y(y^2-3y-x=0) ?
The solution to expand y(y^2-3y-x=0) is y^3-3y^2-xy=0