What is expand ((2x^2+x-3)(2x-1))/3 ?

The solution to expand ((2x^2+x-3)(2x-1))/3 is (4x^3)/3-(7x)/3+1

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expand ((2x^2+x-3)(2x-1))/3

expand

\frac{( 2 x ^{2} + x - 3 ) ( 2 x - 1 )}{3}

\frac{4 x ^{3}}{3} - \frac{7 x}{3} + 1

Solution steps

\frac{( 2 x ^{2} + x - 3 ) ( 2 x - 1 )}{3}

Expand

(2 x^{2} + x - 3) (2 x - 1) : 4 x^{3} - 7 x + 3

= \frac{4 x ^{3} - 7 x + 3}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x ^{3} - 7 x + 3}{3} = \frac{4 x ^{3}}{3} - \frac{7 x}{3} + \frac{3}{3}

= \frac{4 x ^{3}}{3} - \frac{7 x}{3} + \frac{3}{3}

Apply rule

\frac{a}{a} = 1

\frac{3}{3} = 1

= \frac{4 x ^{3}}{3} - \frac{7 x}{3} + 1

- (x - 6 = 4 x + 6 - 5 x)

y d x + (2 x + y) d y

(4 \cdot + y) e^{3}

3 (2 - 3 x)^{2} + e^{(3 x + 5)}

\frac{0.5}{( 15 x + 1 ) ( 150 x + 1 )}

What is expand ((2x^2+x-3)(2x-1))/3 ?
The solution to expand ((2x^2+x-3)(2x-1))/3 is (4x^3)/3-(7x)/3+1