What is expand ((2x-3)^2)/(16) ?

The solution to expand ((2x-3)^2)/(16) is (x^2)/4-(3x)/4+9/16

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expand ((2x-3)^2)/(16)

expand

\frac{( 2 x - 3 ) ^{2}}{16}

\frac{x ^{2}}{4} - \frac{3 x}{4} + \frac{9}{16}

Solution steps

\frac{( 2 x - 3 ) ^{2}}{16}

(2 x - 3)^{2} = 4 x^{2} - 12 x + 9

= \frac{4 x ^{2} - 12 x + 9}{16}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x ^{2} - 12 x + 9}{16} = \frac{4 x ^{2}}{16} - \frac{12 x}{16} + \frac{9}{16}

= \frac{4 x ^{2}}{16} - \frac{12 x}{16} + \frac{9}{16}

Cancel

\frac{4 x ^{2}}{16} : \frac{x ^{2}}{4}

= \frac{x ^{2}}{4} - \frac{12 x}{16} + \frac{9}{16}

Cancel

\frac{12 x}{16} : \frac{3 x}{4}

= \frac{x ^{2}}{4} - \frac{3 x}{4} + \frac{9}{16}

2 ((4, - 1) - 5 (- 3, - 3))

\frac{d}{d θ} ((h) (y (h, θ) - tan (θ) x (h, θ) + 1))

f x \circ g (x - 1)

c d (1 + ab + e)

a b (x - h) + k

What is expand ((2x-3)^2)/(16) ?
The solution to expand ((2x-3)^2)/(16) is (x^2)/4-(3x)/4+9/16