What is expand f(x)dx(=3x^2-8x+3) ?

The solution to expand f(x)dx(=3x^2-8x+3) is f(x)dx=3x^2-8xf(x)dx+3f(x)dx

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expand f(x)dx(=3x^2-8x+3)

expand

f (x) d x (= 3 x^{2} - 8 x + 3)

f (x) d x = 3 x^{2} - 8 x f (x) d x + 3 f (x) d x

Solution steps

f (x) d x (= 3 x^{2} - 8 x + 3)

= f (x) d x (3 = x^{2} - 8 x + 3)

Distribute parentheses

f (x) d x = 3 x^{2} + f (x) d x (- 8 x) + f (x) d x \cdot 3

Apply minus-plus rules

+ (- a) = - a

f (x) d x = 3 x^{2} - 8 x f (x) d x + 3 f (x) d x

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\frac{2 ( x + 1 )}{1 - 2 x - x ^{2}}

2 (x - 40 = 180)

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\frac{( 3 x + 4 ) ^{2}}{x ^{2} + 1}

What is expand f(x)dx(=3x^2-8x+3) ?
The solution to expand f(x)dx(=3x^2-8x+3) is f(x)dx=3x^2-8xf(x)dx+3f(x)dx