What is expand ((n+2)(n-8))/((n-2)(n-3)) ?

The solution to expand ((n+2)(n-8))/((n-2)(n-3)) is (n^2-6n-16)/(n^2-5n+6)

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expand ((n+2)(n-8))/((n-2)(n-3))

expand

\frac{( n + 2 ) ( n - 8 )}{( n - 2 ) ( n - 3 )}

\frac{n ^{2} - 6 n - 16}{n ^{2} - 5 n + 6}

Solution steps

\frac{( n + 2 ) ( n - 8 )}{( n - 2 ) ( n - 3 )}

Expand

(n - 2) (n - 3) : n^{2} - 5 n + 6

= \frac{( n + 2 ) ( n - 8 )}{n ^{2} - 5 n + 6}

Expand

(n + 2) (n - 8) : n^{2} - 6 n - 16

= \frac{n ^{2} - 6 n - 16}{n ^{2} - 5 n + 6}

\frac{2 ( 61 n - 60 )}{n}

(x^{2} - 2)^{3} x d x

\frac{( x ^{2} + 3 )}{( x - 2 ) ^{2}}

(x - 1) (- 2 y + y^{'} (x))

\frac{1}{( t + 1 ) ^{4}}

What is expand ((n+2)(n-8))/((n-2)(n-3)) ?
The solution to expand ((n+2)(n-8))/((n-2)(n-3)) is (n^2-6n-16)/(n^2-5n+6)