What is expand 5(4x-5+3x-1=20) ?

The solution to expand 5(4x-5+3x-1=20) is 35x-30=20

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expand 5(4x-5+3x-1=20)

expand

5 (4 x - 5 + 3 x - 1 = 20)

35 x - 30 = 20

Solution steps

5 (4 x - 5 + 3 x - 1 = 20)

= 5 (4 x - 5 + 3 x - 1 \cdot 20 =)

Distribute parentheses

= 5 \cdot 4 x + 5 (- 5) + 5 \cdot 3 x + 5 (- 1 = 20)

Apply minus-plus rules

+ (- a) = - a

5 \cdot 4 x - 5 \cdot 5 + 5 \cdot 3 x - 5 \cdot 1 = 20

Expand

5 \cdot 4 x - 5 \cdot 5 + 5 \cdot 3 x - 5 \cdot 1 : 35 x - 30

35 x - 30 = 20

(3 y x^{2} - y^{4}) (5 e^{5 t})

2 e (2 + ln (2))

\frac{204}{12}

\frac{( x + 5 ) ^{2}}{x + 6}

\frac{30 ( 0.8 )}{1}

What is expand 5(4x-5+3x-1=20) ?
The solution to expand 5(4x-5+3x-1=20) is 35x-30=20