What is expand x(x-1)(x+Δx(x+Δx-1)) ?

The solution to expand x(x-1)(x+Δx(x+Δx-1)) is Δ^2x^4+Δx^4-Δ^2x^3-2Δx^3+x^3+Δx^2-x^2

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expand x(x-1)(x+Δx(x+Δx-1))

expand

x (x - 1) (x + Δ x (x + Δ x - 1))

Δ^{2} x^{4} + Δ x^{4} - Δ^{2} x^{3} - 2Δ x^{3} + x^{3} + Δ x^{2} - x^{2}

Solution steps

x (x - 1) (x + Δ x (x + Δ x - 1))

Expand

(x - 1) (x + Δ x (x + Δ x - 1)) : Δ^{2} x^{3} + Δ x^{3} - Δ^{2} x^{2} - 2Δ x^{2} + x^{2} + Δ x - x

= x (Δ^{2} x^{3} + Δ x^{3} - Δ^{2} x^{2} - 2Δ x^{2} + x^{2} + Δ x - x)

Expand

x (Δ^{2} x^{3} + Δ x^{3} - Δ^{2} x^{2} - 2Δ x^{2} + x^{2} + Δ x - x) : Δ^{2} x^{4} + Δ x^{4} - Δ^{2} x^{3} - 2Δ x^{3} + x^{3} + Δ x^{2} - x^{2}

= Δ^{2} x^{4} + Δ x^{4} - Δ^{2} x^{3} - 2Δ x^{3} + x^{3} + Δ x^{2} - x^{2}

- 3 (6 x + 3 = - 18 x + 9)

(3 x + 1) + (- 7 x + 9)

\frac{( 2 x - 1 )}{( x - 2 ) ( x - 3 ) ( x - 1 )}

g r a f i c a (2, - 2 \frac{π}{3})

M (\frac{1}{x l})

What is expand x(x-1)(x+Δx(x+Δx-1)) ?
The solution to expand x(x-1)(x+Δx(x+Δx-1)) is Δ^2x^4+Δx^4-Δ^2x^3-2Δx^3+x^3+Δx^2-x^2