What is expand-(x^2(-x+3)^2)/(18) ?

The solution to expand-(x^2(-x+3)^2)/(18) is -(x^4}{18}+\frac{x^3)/3-(x^2)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-(x^2(-x+3)^2)/(18)

expand

- \frac{x ^{2} ( - x + 3 ) ^{2}}{18}

- \frac{x ^{4}}{18} + \frac{x ^{3}}{3} - \frac{x ^{2}}{2}

Solution steps

- \frac{x ^{2} ( - x + 3 ) ^{2}}{18}

(- x + 3)^{2} = x^{2} - 6 x + 9

= - \frac{x ^{2} ( x ^{2} - 6 x + 9 )}{18}

Expand

x^{2} (x^{2} - 6 x + 9) : x^{4} - 6 x^{3} + 9 x^{2}

= - \frac{x ^{4} - 6 x ^{3} + 9 x ^{2}}{18}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{4} - 6 x ^{3} + 9 x ^{2}}{18} = - (\frac{x ^{4}}{18}) - (- \frac{6 x ^{3}}{18}) - (\frac{9 x ^{2}}{18})

= - (\frac{x ^{4}}{18}) - (- \frac{6 x ^{3}}{18}) - (\frac{9 x ^{2}}{18})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{x ^{4}}{18} + \frac{6 x ^{3}}{18} - \frac{9 x ^{2}}{18}

Cancel

\frac{6 x ^{3}}{18} : \frac{x ^{3}}{3}

= - \frac{x ^{4}}{18} + \frac{x ^{3}}{3} - \frac{9 x ^{2}}{18}

Cancel

\frac{9 x ^{2}}{18} : \frac{x ^{2}}{2}

= - \frac{x ^{4}}{18} + \frac{x ^{3}}{3} - \frac{x ^{2}}{2}

\frac{1}{y ( x + y + 1 )}

\frac{( 2 + 2 sin ( θ ) ) ^{2}}{2}

\frac{2}{( x - 6 ) ^{2}}

(2 n + 1)^{2}

\frac{x + 5}{4 ( x - 5 )}

What is expand-(x^2(-x+3)^2)/(18) ?
The solution to expand-(x^2(-x+3)^2)/(18) is -(x^4}{18}+\frac{x^3)/3-(x^2)/2