What is expand ((x-3)(2x+5))/2 ?

The solution to expand ((x-3)(2x+5))/2 is x^2-x/2-15/2

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expand ((x-3)(2x+5))/2

expand

\frac{( x - 3 ) ( 2 x + 5 )}{2}

x^{2} - \frac{x}{2} - \frac{15}{2}

Solution steps

\frac{( x - 3 ) ( 2 x + 5 )}{2}

Expand

(x - 3) (2 x + 5) : 2 x^{2} - x - 15

= \frac{2 x ^{2} - x - 15}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 x ^{2} - x - 15}{2} = \frac{2 x ^{2}}{2} - \frac{x}{2} - \frac{15}{2}

= \frac{2 x ^{2}}{2} - \frac{x}{2} - \frac{15}{2}

Divide the numbers:

\frac{2}{2} = 1

= x^{2} - \frac{x}{2} - \frac{15}{2}

\frac{2}{( x ^{2} + 4 ) ( x - a )}

δ (3 x + 5)

e^{j (wt - 1)}

(- 4 x - 6 x) (- 1, 5) \cdot (- 2, 7) 1.5

f (4)^{f (h + k)}

What is expand ((x-3)(2x+5))/2 ?
The solution to expand ((x-3)(2x+5))/2 is x^2-x/2-15/2