What is expand (n+1)λ^{ln(n+2)} ?

The solution to expand (n+1)λ^{ln(n+2)} is nλ^{ln(n+2)}+λ^{ln(n+2)}

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expand (n+1)λ^{ln(n+2)}

expand

(n + 1) λ^{l n (n + 2)}

n λ^{l n (n + 2)} + λ^{l n (n + 2)}

Solution steps

(n + 1) λ^{l n (n + 2)}

= λ^{l n (n + 2)} (n + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = λ^{l n (n + 2)}, b = n, c = 1

= λ^{l n (n + 2)} n + λ^{l n (n + 2)} \cdot 1

= n λ^{l n (n + 2)} + 1 \cdot λ^{l n (n + 2)}

Multiply:

1 \cdot λ^{l n (n + 2)} = λ^{l n (n + 2)}

= n λ^{l n (n + 2)} + λ^{l n (n + 2)}

(1 - e^{- 0.6 x})^{2}

\frac{( x ^{2} - 1 ) ^{2}}{x ^{3}}

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6 (2 x - 25 = - 18)

(e^{y} + 1)^{3}

What is expand (n+1)λ^{ln(n+2)} ?
The solution to expand (n+1)λ^{ln(n+2)} is nλ^{ln(n+2)}+λ^{ln(n+2)}