What is expand ((x-2)(x-8))/2 ?

The solution to expand ((x-2)(x-8))/2 is (x^2)/2-5x+8

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expand ((x-2)(x-8))/2

expand

\frac{( x - 2 ) ( x - 8 )}{2}

\frac{x ^{2}}{2} - 5 x + 8

Solution steps

\frac{( x - 2 ) ( x - 8 )}{2}

Expand

(x - 2) (x - 8) : x^{2} - 10 x + 16

= \frac{x ^{2} - 10 x + 16}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} - 10 x + 16}{2} = \frac{x ^{2}}{2} - \frac{10 x}{2} + \frac{16}{2}

= \frac{x ^{2}}{2} - \frac{10 x}{2} + \frac{16}{2}

Divide the numbers:

\frac{10}{2} = 5

= \frac{x ^{2}}{2} - 5 x + \frac{16}{2}

Divide the numbers:

\frac{16}{2} = 8

= \frac{x ^{2}}{2} - 5 x + 8

\frac{( x + 7 ) ^{4}}{( x - 4 ) ^{2}}

\frac{2 x}{( x + 6 ) ^{2}}

\frac{d}{d t} ((x) (- 1.25 x^{2} + 5 x))

\frac{( - a - 5 ) ^{2}}{5 ( a ^{2} + 5 )}

y, x + 2 y = 1

What is expand ((x-2)(x-8))/2 ?
The solution to expand ((x-2)(x-8))/2 is (x^2)/2-5x+8