What is expand b/((x+b+1)(x+1)) ?

The solution to expand b/((x+b+1)(x+1)) is b/(bx+x^2+2x+b+1)

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expand b/((x+b+1)(x+1))

expand

\frac{b}{( x + b + 1 ) ( x + 1 )}

\frac{b}{b x + x ^{2} + 2 x + b + 1}

Solution steps

\frac{b}{( x + b + 1 ) ( x + 1 )}

Expand

(x + b + 1) (x + 1) : b x + x^{2} + 2 x + b + 1

= \frac{b}{b x + x ^{2} + 2 x + b + 1}

5 (6 x + 7 + 4 = 29)

(3) + (3 - 3 x) d x

(x y + y^{2}) d x - (x^{2}) d y

(x + δ)^{2} - 9 (x + δ) - 6

\frac{2 x}{( x + 1 ) ( 2 x + 1 ) ( x + 2 )}

What is expand b/((x+b+1)(x+1)) ?
The solution to expand b/((x+b+1)(x+1)) is b/(bx+x^2+2x+b+1)