What is expand-2(e^x+xe^x) ?

The solution to expand-2(e^x+xe^x) is -2e^x-2e^xx

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expand-2(e^x+xe^x)

expand

- 2 (e^{x} + x e^{x})

- 2 e^{x} - 2 e^{x} x

Solution steps

- 2 (e^{x} + x e^{x})

= - 2 (e^{x} + e^{x} x)

Apply the distributive law:

a (b + c) = ab + a c

a = - 2, b = e^{x}, c = x e^{x}

= - 2 e^{x} + (- 2) x e^{x}

Apply minus-plus rules

+ (- a) = - a

= - 2 e^{x} - 2 e^{x} x

\frac{n ^{2}}{( 2 n - 1 ) ( 2 n + 1 )}

\frac{x}{( x + 1 ) ( x - 4 )}

- 2 (1 - 6 r = 82)

(2 π + i 2 πn) \cdot (2 π - i \cdot 2 πn)

\frac{L ^{2} ( P + W L )}{16}