What is expand (3(k^2+3k+2))/2 ?

The solution to expand (3(k^2+3k+2))/2 is (3k^2)/2+(9k)/2+3

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expand (3(k^2+3k+2))/2

expand

\frac{3 ( k ^{2} + 3 k + 2 )}{2}

\frac{3 k ^{2}}{2} + \frac{9 k}{2} + 3

Solution steps

\frac{3 ( k ^{2} + 3 k + 2 )}{2}

Expand

3 (k^{2} + 3 k + 2) : 3 k^{2} + 9 k + 6

= \frac{3 k ^{2} + 9 k + 6}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 k ^{2} + 9 k + 6}{2} = \frac{3 k ^{2}}{2} + \frac{9 k}{2} + \frac{6}{2}

= \frac{3 k ^{2}}{2} + \frac{9 k}{2} + \frac{6}{2}

Divide the numbers:

\frac{6}{2} = 3

= \frac{3 k ^{2}}{2} + \frac{9 k}{2} + 3

\frac{( x - 3 ) ( x + 2 )}{( x + 3 )}

\frac{( 2 x ^{2} - 6 x + 9 ) ^{2}}{2}

(35) (67)

(x^{2} y - x^{2} + y - 1) d y

(6 e + 7 z) (6 e - 7 z)

What is expand (3(k^2+3k+2))/2 ?
The solution to expand (3(k^2+3k+2))/2 is (3k^2)/2+(9k)/2+3