What is expand ((b-1)^2(a+1))/(a(b-2)) ?

The solution to expand ((b-1)^2(a+1))/(a(b-2)) is (b^2a+b^2-2ba-2b+a+1)/(ba-2a)

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expand ((b-1)^2(a+1))/(a(b-2))

expand

\frac{( b - 1 ) ^{2} ( a + 1 )}{a ( b - 2 )}

\frac{b ^{2} a + b ^{2} - 2 ba - 2 b + a + 1}{ba - 2 a}

Solution steps

\frac{( b - 1 ) ^{2} ( a + 1 )}{a ( b - 2 )}

(b - 1)^{2} = b^{2} - 2 b + 1

= \frac{( b ^{2} - 2 b + 1 ) ( a + 1 )}{a ( b - 2 )}

Expand

a (b - 2) : ba - 2 a

= \frac{( b ^{2} - 2 b + 1 ) ( a + 1 )}{ba - 2 a}

Expand

(b^{2} - 2 b + 1) (a + 1) : b^{2} a + b^{2} - 2 ba - 2 b + a + 1

= \frac{b ^{2} a + b ^{2} - 2 ba - 2 b + a + 1}{ba - 2 a}

2 (- 2 x + y = 4)

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\frac{5 ( x - 32 )}{9}

(9 x^{2} + x^{4}) d x

What is expand ((b-1)^2(a+1))/(a(b-2)) ?
The solution to expand ((b-1)^2(a+1))/(a(b-2)) is (b^2a+b^2-2ba-2b+a+1)/(ba-2a)