What is expand parametric(x+y+z=4) ?

The solution to expand parametric(x+y+z=4) is i=4epa^2mcr^2tx+i=4epa^2mcr^2ty+i=4epa^2mcr^2tz

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expand parametric(x+y+z=4)

expand

p a r am e t r i c (x + y + z = 4)

i = 4 e p a^{2} m c r^{2} t x + i = 4 e p a^{2} m c r^{2} t y + i = 4 e p a^{2} m c r^{2} t z

Solution steps

p a r am e t r i c (x + y + z = 4)

= e i p aam crr t (x + y + 4 = z)

Expand

p a r am e t r i c (x + y + z = 4) : i (e p a^{2} m c r^{2} t x + e p a^{2} m c r^{2} t y + e p a^{2} m c r^{2} t z) = 4

i (e p a^{2} m c r^{2} t x + e p a^{2} m c r^{2} t y + e p a^{2} m c r^{2} t z) = 4

Expand

i = 4 (e p a^{2} m c r^{2} t x + e p a^{2} m c r^{2} t y + e p a^{2} m c r^{2} t z) : i = 4 e p a^{2} m c r^{2} t x + i = 4 e p a^{2} m c r^{2} t y + i = 4 e p a^{2} m c r^{2} t z

i = 4 e p a^{2} m c r^{2} t x + i = 4 e p a^{2} m c r^{2} t y + i = 4 e p a^{2} m c r^{2} t z

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cos ((n + \frac{1}{2}) π)

15 (2 \frac{1}{3})

1.5 (x - 2 y)^{2} d y

(\frac{3}{x - 2})^{2}

What is expand parametric(x+y+z=4) ?
The solution to expand parametric(x+y+z=4) is i=4epa^2mcr^2tx+i=4epa^2mcr^2ty+i=4epa^2mcr^2tz