What is expand 1/((s^2-9)(s+9)) ?

The solution to expand 1/((s^2-9)(s+9)) is 1/(s^3+9s^2-9s-81)

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expand 1/((s^2-9)(s+9))

expand

\frac{1}{( s ^{2} - 9 ) ( s + 9 )}

\frac{1}{s ^{3} + 9 s ^{2} - 9 s - 81}

Solution steps

\frac{1}{( s ^{2} - 9 ) ( s + 9 )}

Expand

(s^{2} - 9) (s + 9) : s^{3} + 9 s^{2} - 9 s - 81

= \frac{1}{s ^{3} + 9 s ^{2} - 9 s - 81}

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What is expand 1/((s^2-9)(s+9)) ?
The solution to expand 1/((s^2-9)(s+9)) is 1/(s^3+9s^2-9s-81)