What are the solutions to the equation (3m-1)^2+12=0 ?

The solutions to the equation (3m-1)^2+12=0 are m= 1/3+i(2sqrt(3))/3 ,m= 1/3-i(2sqrt(3))/3

Find the zeros of (3m-1)^2+12=0

The zeros of (3m-1)^2+12=0 are m= 1/3+i(2sqrt(3))/3 ,m= 1/3-i(2sqrt(3))/3

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(3 m - 1)^{2} + 12 = 0

m = \frac{1}{3} + i \frac{2 3}{3}, m = \frac{1}{3} - i \frac{2 3}{3}

Solution steps

(3 m - 1)^{2} + 12 = 0

Move

12

to the right side

(3 m - 1)^{2} = - 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 m - 1 = - 12 : m = \frac{1}{3} + i \frac{2 3}{3}

Solve

3 m - 1 = - - 12 : m = \frac{1}{3} - i \frac{2 3}{3}

The solutions to the quadratic equation are:

m = \frac{1}{3} + i \frac{2 3}{3}, m = \frac{1}{3} - i \frac{2 3}{3}

6 (h + \frac{1}{2}) - 1 = 4 h - 8

\frac{9}{5} - \frac{9}{2}

3 v + 2 = 4 v - 6

\frac{x + 9 ( 5 + x )}{5} = 9 - x

7 - 7 (x - 8) \leq 2 x + 18

What are the solutions to the equation (3m-1)^2+12=0 ?
The solutions to the equation (3m-1)^2+12=0 are m= 1/3+i(2sqrt(3))/3 ,m= 1/3-i(2sqrt(3))/3
Find the zeros of (3m-1)^2+12=0
The zeros of (3m-1)^2+12=0 are m= 1/3+i(2sqrt(3))/3 ,m= 1/3-i(2sqrt(3))/3