What is expand (2ay+1)(e^2y^2-ay-1) ?

The solution to expand (2ay+1)(e^2y^2-ay-1) is 2e^2ay^3+e^2y^2-2a^2y^2-3ay-1

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expand (2ay+1)(e^2y^2-ay-1)

expand

(2 a y + 1) (e^{2} y^{2} - a y - 1)

2 e^{2} a y^{3} + e^{2} y^{2} - 2 a^{2} y^{2} - 3 a y - 1

Solution steps

(2 a y + 1) (e^{2} y^{2} - a y - 1)

Distribute parentheses

= 2 a y e^{2} y^{2} + 2 a y (- a y) + 2 a y (- 1) + 1 \cdot e^{2} y^{2} + 1 \cdot (- a y) + 1 \cdot (- 1)

Apply minus-plus rules

+ (- a) = - a

= 2 e^{2} a y^{2} y - 2 aa yy - 2 \cdot 1 \cdot a y + 1 \cdot e^{2} y^{2} - 1 \cdot a y - 1 \cdot 1

Simplify

2 e^{2} a y^{2} y - 2 aa yy - 2 \cdot 1 \cdot a y + 1 \cdot e^{2} y^{2} - 1 \cdot a y - 1 \cdot 1 : 2 e^{2} a y^{3} + e^{2} y^{2} - 2 a^{2} y^{2} - 3 a y - 1

= 2 e^{2} a y^{3} + e^{2} y^{2} - 2 a^{2} y^{2} - 3 a y - 1

\frac{6 s}{( s + 3 ) ( s ^{2} + 5 )}

3 ((- 2, 5, 1) - (3, 1, 1))

\frac{( x - 3 ) ( x - 10 )}{2}

9^{2} - 24 + 16

\frac{5 - 2 x ^{2}}{( x + 1 ) ^{2}}

What is expand (2ay+1)(e^2y^2-ay-1) ?
The solution to expand (2ay+1)(e^2y^2-ay-1) is 2e^2ay^3+e^2y^2-2a^2y^2-3ay-1