What is expand (9pi(-2ln(3)-1))/(40) ?

The solution to expand (9pi(-2ln(3)-1))/(40) is -(9piln(3))/(20)-(9pi)/(40)

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expand (9pi(-2ln(3)-1))/(40)

expand

\frac{9 π ( - 2 ln ( 3 ) - 1 )}{40}

- \frac{9 π ln ( 3 )}{20} - \frac{9 π}{40}

Solution steps

\frac{9 π ( - 2 ln ( 3 ) - 1 )}{40}

Expand

9 π (- 2 ln (3) - 1) : - 18 π ln (3) - 9 π

= \frac{- 18 π ln ( 3 ) - 9 π}{40}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 18 π ln ( 3 ) - 9 π}{40} = - \frac{18 π ln ( 3 )}{40} - \frac{9 π}{40}

= - \frac{18 π ln ( 3 )}{40} - \frac{9 π}{40}

Cancel

\frac{18 π ln ( 3 )}{40} : \frac{9 π ln ( 3 )}{20}

= - \frac{9 π ln ( 3 )}{20} - \frac{9 π}{40}

x ((x - 4) (x - 3)) ((x - 2) (x - 1))

- \frac{( - x + 15 ) ( - x + 5 )}{2}

2 e^{y} (x + 4) y^{3}

cos ((n + 1) α)

5 (e + 3 h)^{2}

What is expand (9pi(-2ln(3)-1))/(40) ?
The solution to expand (9pi(-2ln(3)-1))/(40) is -(9piln(3))/(20)-(9pi)/(40)