What is expand ((-3-x)^2)/2 ?

The solution to expand ((-3-x)^2)/2 is (x^2)/2+3x+9/2

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expand ((-3-x)^2)/2

expand

\frac{( - 3 - x ) ^{2}}{2}

\frac{x ^{2}}{2} + 3 x + \frac{9}{2}

Solution steps

\frac{( - 3 - x ) ^{2}}{2}

(- 3 - x)^{2} = 9 + 6 x + x^{2}

= \frac{9 + 6 x + x ^{2}}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 + 6 x + x ^{2}}{2} = \frac{9}{2} + \frac{6 x}{2} + \frac{x ^{2}}{2}

= \frac{9}{2} + \frac{6 x}{2} + \frac{x ^{2}}{2}

Divide the numbers:

\frac{6}{2} = 3

= \frac{9}{2} + 3 x + \frac{x ^{2}}{2}

Rewrite in standard form

= \frac{x ^{2}}{2} + 3 x + \frac{9}{2}

\frac{a s + b + 3 a + 1}{s ( s + 1 ) ( s + 2 )}

2 a - (x - c)^{2} + y^{2}

(x^{7})^{2}

\frac{( x + h ) ^{2} - 3 ( x + h ) + 4}{h}

(x + 3) + \frac{x + 7}{2 - x}

What is expand ((-3-x)^2)/2 ?
The solution to expand ((-3-x)^2)/2 is (x^2)/2+3x+9/2