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Popular >

simplify e^{(2n+1)i}

Solution

simplify

e^{(2 n + 1) i}

Solution

cos (2 n + 1) + i sin (2 n + 1)

Solution steps

e^{(2 n + 1) i}

Apply imaginary number rule:

e^{ia} = cos (a) + i sin (a)

= cos (2 n + 1) + i sin (2 n + 1)

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Frequently Asked Questions (FAQ)

What is e^{(2n+1)i} ?
The solution to e^{(2n+1)i} is cos(2n+1)+isin(2n+1)