What is expand (f\circ g)(x^2+5)(x^2-1) ?

The solution to expand (f\circ g)(x^2+5)(x^2-1) is \circ fgx^4+4\circ fgx^2-5\circ fg

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expand (f\circ g)(x^2+5)(x^2-1)

expand

(f \circ g) (x^{2} + 5) (x^{2} - 1)

\circ f g x^{4} + 4 \circ f g x^{2} - 5 \circ f g

Solution steps

(f \circ g) (x^{2} + 5) (x^{2} - 1)

= (\circ f g) (x^{2} + 5) (x^{2} - 1)

Expand

(x^{2} + 5) (x^{2} - 1) : x^{4} + 4 x^{2} - 5

= (f \circ g) (x^{4} + 4 x^{2} - 5)

Expand

(f \circ g) (x^{4} + 4 x^{2} - 5) : \circ f g x^{4} + 4 \circ f g x^{2} - 5 \circ f g

= \circ f g x^{4} + 4 \circ f g x^{2} - 5 \circ f g

l imh \Rightarrow 0 f (x + h) - f (x) h

\frac{4 ( x + h ) ^{2}}{h}

(2 - 3 a b^{2})^{14}

\frac{x + 13}{( x + 1 ) ( x - 10 )}

\frac{2 x ^{2}}{( x - 3 ) ( x + 5 )}

What is expand (f\circ g)(x^2+5)(x^2-1) ?
The solution to expand (f\circ g)(x^2+5)(x^2-1) is \circ fgx^4+4\circ fgx^2-5\circ fg